Problem: In a survey at an airport, 55 travelers said that last year they had been to Spain, 53 to 1 France and 79 to Germany, 18 had been to Spain and France. 17 to Spain and Germany and 25 to France and Germany, while 10 had to all three countries. How many travelers took part in the survey?

View all: AGRANI BANK LTD (SO-ADUITOR) WRITTEN QUESTION (MATH) SOLVE | 2018

Correct Answer: 137

Explanation:

Let, total number of travelers = n (A U B U C)Number of traveler who had been to Spain, n(A) = 55

Number of traveler who had been to France, n(B) = 53Number of traveler who had been to Germany. n((C) = 79

Number of traveler who had been to Spain and France. n($A\bigcap_{}^{}B$) = 18

Number of traveler who had been to Spain aml Germany,n($A\bigcap_{}^{}C$)= 17

Number 01‘ traveler who had been to France and Germany. n ($B\bigcap_{}^{}C$) = 25

Number of traveler who had been to all three countries. n ($A\bigcap_{}^{}B\bigcup_{}^{}C$)= 10

SO, Travelers took part in the survey= $(A\bigcup_{}^{}B\bigcup_{}^{}C)$= n(A)+n(B)+ n(C)-n($A\bigcap_{}^{}B$)-n($B\bigcap_{}^{}C$)-n($A\bigcap_{}^{}C$)+n($A\bigcap_{}^{}B\bigcup_{}^{}C$)

= 55+53+79-18-17-25+10=197-60= 137

Write Reply...
You should read | Topics/Questions
User Avatar

Articles

0

Comments

0

Rating

0