Ashifur September 9, 2023 - 17:37
Problem: length of each equal side of an isosceles triangle is 10cm and the mcuded angle between those two sides is 45°. Find the area of the triangle.

View all: BANGLADESH KRISHI BANK LTD (OFFICER-CASH) WRITTEN QUESTION (MATH) SOLVE | 2018

Correct Answer: 22$\sqrt{2}$

Explanation:

Let, x be the perpendicular drawn from the vertex of triangle

We know, Sin 45 ° = $\frac{1}{\sqrt{2}}$

=> $\frac{1}{\sqrt{2}}$ = $\frac{x}{10}$

=> x = $\frac{10}{\sqrt{2}}$

Area of triangle = $\frac{1}{2}$ x Base x Height

= $\frac{1}{2}$ x 10 x $\frac{10}{\sqrt{2}}$ = 25$\sqrt{2}$

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