560
Let, the number of male be 2:
Then the number of female be 4):
Total number of male and female = x + 4x = 5x
According to the question,
x+140:4x=2:3
=> $\frac{x+140}{4x}=\frac{2}{3}$
=> 3x + 420 = 8x
=> 5x = 420
=> x = 84
Total number of member be = 5x + 140
= 5 X 84 + 140
= 420 + 140 = 560
5%
Defective products =$\frac{1}{5}$
Hence Good products = (I -$\frac{1}{5}$) =$\frac{4}{5}$
Rejected of good products =$\frac{4}{5}$ of $\frac{1}{20}$= $\frac{1}{25}$
Rejected of defective products = $\frac{1}{5}$ of $\frac{4}{5}$ = $\frac{4}{25}$
Total rejected products = $\frac{1}{25}$+ $\frac{4}{5}$ = $\frac{1}{25}$
Sold of defective products = $\frac{1}{5}$- $\frac{4}{25}$ = $\frac{1}{25}$
Total rejected products =1 — $\frac{1}{5}$ = $\frac{4}{5}$
Among $\frac{4}{5}$ sold products defective = $\frac{1}{25}$
Among 100 sold products defective = $\frac{100 \cdot 5}{25 \cdot 4}$= 5%
36 Kms
Let, Rahim drives x km. at 72 km/h
(48 —x) km is driven at 48 km/h
According to question
$\frac{x}{72}$ + $\frac{48-x}{48}$ = 45 x $\frac{1}{60}$ = $\frac{3}{4}$
=> $\frac{2x + 3(48-x)}{144}$ = $\frac{3}{4}$
=> $\frac{144-x}{36} = $\frac{3}{4}$$
=> —x=—36
=> x=36
Live ten miles or less 70% and use company transport 31$\frac{3}{7}$
Let, total employees = 100
30% live over ten miles
30% employee = 30 employees
Live 10 mile or less 10 mile = (100 — 30)% = 70%
60% of 30 employee who live over 10 miles =$\frac{60 \cdot 30}{100}$= 18 employees
The employees 40% use transport = $\frac{60 \cdot 100}{100}$= 40 employees
The employees use transport who live 10 or less 10 miles = (40 – 18) = 22
Among 70 employees use transport = 22
Among 100 employees use transport = $\frac{22 \cdot 100}{70}$ = $\frac{220}{7}$ = 31$\frac{3}{7}$
