One of the faster workers can do thejob in 50 days.
Let, each of the faster workers can do the job in x days
Slower worker can do the job in 2x days.
3 workers in one day can do = 1x+1x+12x portion
= 52x portion
3 workers In 20 days can do 52x x 20 — 50x Portlon
50x =1
x = 50
Question 2:
20√3 ft
ΔABD is a equal side triangle
∠ADB = 60°
∠BAD = 60°
∠DBC = 30° & ∠BDC = 120°
∠DCB = 30°
in ΔBDC, ∠DBC = ∠DCB
BD = DC = 20
AC=AD+DC=20+20=40
ABC is a right triangle, AC is hypotenuse
AC² = AB²+ BC²
BC² = AC² — A8² = 40²-20² = 1200
BC = √400×3=20√3
3113 %
As property P.1 is 20% less than purchase price,
Purchase ofP1= 100000 x 31100%80%
= Tk. 125000
Loss = Tk. 25000
Mr X made profit from P2 = Tk. 25000
The purchase price of P2 was = Tk. 100000 — Tk. 25000
= T k. 75000
Profit in P2 was =312500075000x100 = 3113 %
Question 4:
2±√10
2x−2+3x+3=1
=> 2x+6+3x−6(x−2)(x+3)=1
=> 5xx2+x−6=1
=> x2+x−6=5x
=> x2−4x−6=0
=> x=−(−4)±√(−4)2−4x1x(−6)2×1
=> x = 2±√10
913
In first 8 hours he gets = Tk. 8 x 8 =TK 64
He gets from ever time = Tk. (80 – 64) = Tk. 16
Overtime (excess of 8 hours duty) rate = Tk. 832 = Tk. 12 per hour
Overtime =1612 =43 hours
Total time he works = (8 +43) hours = 913 hours
9254

80
Let, Number of older children = x
Number of younger children = (200 – x)
x x 2 + 3(200 —x) = 480
2x+600—3x=480
x = 120
Number of younger children = (200 — 120) = 80
10 years
Here,
R = 5?
T =?
l= 15000Tk.
P = 30000Tk.
A = 45000Tk.
Let,
Interest be, I = 3x
and investment be, P = 6x
Amount be, A = 3x + 6x = 9::
According to the question,
9x = 45000
x = 450009 = 5000 Tk
Interest, 1 = 3x = 3 x 5000 = 15000Tk
Investment, P = 6x = 6 x 5000 = 30000Tk
We know,
T = 100xIPR
=100×1500030000×5 =10
10
Let, the age of C = x
The age ofB = 2::
The age ofA =2x+ 2
According to the question,
x+2x+2x+23=9
=> 5x+ 2 =27
=> 5x=27—2
=> 5x=25
=> x=5
Now, Age of Be will be = 2x years
=2×5 =10