TK 50
At 25% discount,
If asking price Tk. 100 discounted price Tk. (100 — 25) or Tk. 75
If asking price Tk. so discounted price Tk. $\frac{75×80}{100}$ = Tk. 60
At 20% Profit a
If selling price Tk. 120 then cost price = Tk. 100
If selling price Tk. 60 then cost price = Tk. $\frac{100×60}{120}$ = Tk. 50
100000
3$L\sqrt{2}$
CE=BC=CD=L
BD = Diagonal of ABCD
AB² + AD² = BD²
L² + L² = BD²
BD = $L\sqrt{2}$
Thus, BE = DB = BD = $L\sqrt{2}$
Perimeter = $L\sqrt{2}$ + $L\sqrt{2}$ + $L\sqrt{2}$= 3$L\sqrt{2}$
$6\sqrt{2}$ feet
Area of the floor = 9 x 12 = 108 sq.feet
Area of the carpet = 1%8 sq.feet = 54 sq.feet
Ratio of the dimension of the floor = 9 : 12 = 3 : 4
Ratio of the dimension of the carpet = 3 : 4
Let, width & length of the carpet = 3x & 4x
3x x 4x = 54
12x² = 54
x = $\frac{3}{\sqrt{2}}$
Length of the carpet = 4 x $\frac{3}{\sqrt{2}}$ = $6\sqrt{2}$ feet.
Number of pen is 3
Let, the number of pen that is sold at 10 Tk loss per pen = x
Total loss by selling the pen = 10x Tk
Total profit by selling the pen = 35 (22 -x) Tk
According to the question,
35 (22 —x) — 10x = 635
=> 770 — 35x — 10x = 635
=> 770 — 635 = 45x
=> 45x = 135
=> x = 3
