Correct Answer: $\frac{193}{15}$ is not an integer.

Explanation:

we let, consecutive integers are (x – 7), (x- 6), (x- 5), (x – 4), (x- 3), (x – 2), (x – 1), x, (x+ I), (x+ 2), (X + 3), (x + 4), (x+ 5), (x+ 6), (x + 7)

According to question

x+(x+1) +(x+2)+(x+3) +(x+4) +(x+ 5) + (x+6)+ (x+7)+(x-7)+(x-6)+(x-5) +(x-4) +(x-3) + (x- 2)+(x- 1) = 88

=> 15x + 28 – 28 = 88

=>15x = 88

x = $\frac{88}{15}$

The largest number is (x + 7) = $\frac{88}{15}$ +7 = $\frac{88+105}{15}$ = $\frac{193}{15}$

But. here $\frac{193}{15}$ is not an integer.

So the data given in the question may not be consistent.