A farmer sold a cow and an ox for Tk. 80,000 and got a profit of 20% on the cow and 25% on the ox. If he sells the cow and the ox for Tk. 82,000 he \gets a profit of 25% on the cow and 20% on the ox. Find the individual cost price of the cow and ox.

Ashifur September 9, 2023 - 18:12

Problem: A farmer sold a cow and an ox for Tk. 80,000 and got a profit of 20% on the cow and 25% on the ox. If he sells the cow and the ox for Tk. 82,000 he \gets a profit of 25% on the cow and 20% on the ox. Find the individual cost price of the cow and ox.

View all: UTTARA BANK LTD (DO) WRITTEN QUESTION (MATH) SOLVE | 2018

Correct Answer: The cost of the cow is TK.53.061.22 & The cost of the ox is TK.13,061.22

Explanation:

Let. the cost price of Cow be X TK

And the cost price of Ox be Y TK

According to the questions.120%x+l25%y = 80,000

=> $\frac{120X}{100}+\frac{125y}{100}=80,000$

=> 120x + 125y = 80,000 x 100=> 24x + 25 = 16,00,000 …………….(i)

Again. 125%x + 120%y = 82,000

=> $\frac{125x}{100}+\frac{120y}{100}$=82,000

=> 125x + 120y = 82,000 x 100

so, 25x + 24y = 16,40,000 ……………………….(ii)

(i) x 25 – (ii) x 24

600x + 625y = 4,00,00,000

600x+ 576y = 3,93,60,000

=> 49y = 6,40,000

y = 13,061,22

putting the valu of y =13,061,22 in equation (i) we get

24x=16,00,000-3,26,530.61

=> 24x = 12,73,469.4

so, x=53,061.22

The cost of the cow is TK.53,061,22 & The cost of the ox is TK.13,061.22

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