Problem: A person invested $\frac{2}{3}$ rd of his capital at th at 3%,$\frac{1}{6}$ th at 6% and the remainder at 12%. Find out the amount of capital if his annual income is Tk. 25.

View all: RAJSHAHI KRISHI UNNAYAN BANK (SO)| 1$^{st}$ CLASS WRITTEN QUESTION (MATH) SOLVE | 2015

Correct Answer: ans: 500 Tk.

Explanation:

Let, the capital be x Tk.

$\frac{2}{3}$ rd of his capital be $\frac{2x}{3}$ TK

$\frac{1}{6}$ th of his capital be $\frac{x}{6}$

Rest of the capital be = $(x-\frac{2x}{3}-\frac{x}{6})$

= $\frac{6x-4x-x}{6}$ = $\frac{x}{6}$

According to the question.

$(\frac{2x}{3}\times \frac{3}{100}\times 1)$ + $(\frac{x}{6}\times \frac{6}{100}\times 1)$ = 25

=> $\frac{x}{50}+\frac{x}{50}+\frac{x}{50}$ = 25

=> $\frac{2x+x+2x}{100}$ = 25

=> 5x =100×25

=> $\frac{25\times 100}{5}$

x = 500 TK

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