Problem: If the sum of five consecutive integers is S, what is the largest of those integers in terms of S?

View all: BANGLADESH BANK OFFICER | WRITTEN QUESTION (MATH) SOLVE | 2015

Correct Answer: ans: The Largest integer $\frac{s+10}{5}$

Explanation:

Let, 5 consecutive integers are x, x + l, x + 2, x + 3 and x + 4

According to the questionx+(x+1)+(x+2)+(x+3)+(x+4)=S

=> 5x +10 = S

=> 5x = S -10

=> x = $\frac{s-10}{5}$

The Largest integer =x + 4

= $\frac{s-10}{5}$+4

= $\frac{s-10+20}{5}$

= $\frac{s+10}{5}$

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