Problem: If the sum of five consecutive integers is S, what is the largest of those integers in terms of S?
View all: BANGLADESH BANK OFFICER | WRITTEN QUESTION (MATH) SOLVE | 2015
Correct Answer: ans: The Largest integer $\frac{s+10}{5}$
Explanation:
Let, 5 consecutive integers are x, x + l, x + 2, x + 3 and x + 4
According to the questionx+(x+1)+(x+2)+(x+3)+(x+4)=S
=> 5x +10 = S
=> 5x = S -10
=> x = $\frac{s-10}{5}$
The Largest integer =x + 4
= $\frac{s-10}{5}$+4
= $\frac{s-10+20}{5}$
= $\frac{s+10}{5}$