Correct Answer: ans. 400 TK

Explanation:

1n 6 days Abdul can finish the whole = 1 work

In 1 day Abdul can finish the whole = $\frac{1}{6}$ part of the work

Again,

In 8 days Bokul can finish the whole = 1 work

In 1 day Bokul can finish the whole =$\frac{1}{8}$ part of the work

So, In 1 \both Abdul & Bokul together can finish = ($\frac{1}{6}$+ $\frac{1}{8}$) = $\frac{7}{24}$ part of the work

Again in 3 days, Abdul, Bokul & Chinu can finish the whole = 1 work

In 1 day, Abdul, Bokul & Chinu can finish the whole =$\frac{1}{3}$part of the work

In 1 day only Chinu can finish = $\frac{1}{3}-\frac{7}{24}= \frac{1}{24}$ part of the work

So, the ratio of 1 day’s work done by Abdul, Bokul & Chinu respectively = $\frac{1}{6} : \frac{1}{8} : \frac{1}{24}$ = 4:3:1

Chinu is to be paid = (3200 x $\frac{1}{4+3+1}$) = 400 Tk.