Ashifur August 8, 2023 - 14:20
Problem: The length and width of a rectangular field are 24 metre and 12 metre respectively. If the length and width of the field is increased by 6%. What will be the percentage of increase of the area of the field?

View all: AB BANK LTD. | PROBATIONARY OFFICER | WRITTEN QUESTION (MATH) SOLVE | 1997

Correct Answer: 12.36 %

Explanation:

Length and with of the rectangular field is 24 metre and 12 metre respectively

Area of the rectangular 24 x 12 sq. metre = 288 sq. metre

Both length and width increased by 6%

Increased length = 24 + 6% of 24

= $\frac{24 +1.44}{100}$

= 25.44 metre

Increased width = 12 + 6% of 12

= 12 + 0.72 = 12.72 metre

Total area after increased = (25.44 x 12.72) sq. metre

= 323.5968 sq. metre

So, Increased percentage = $\frac{(323.5968-288)\cdot100)}{288}$ = 12.36 %

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