Ashifur August 8, 2023 - 14:57
Problem: A man started at 8 a.m. from his home, walked at the rate of 3 km/hr and reached his office 45 minute late. The next day he started at the same time and walked at the rate of 5 km/hr and reached his office 15 minutes earlier. What is the distance between his office and home?

View all: MERCANTILE BANK | WRITTEN QUESTION(MATH) SOLVE | 2004

Correct Answer: 7.5 km

Explanation:

Let, the distance between office and home =x km.

3 km walk in = 1 hourx km walk in = $\frac{x}{3}$ hour

Actual reaching time = $\frac{x}{3}$ – $\frac{45}{60}$ hour.

= $\frac{x}{3}$ – $\frac{3}{4}$ hour.

And 5 km walk in = 1 hour.

x km walk in =$\frac{x}{5}$ hour.

Acutal reaching time =$\frac{x}{5}$ + $\frac{15}{16}$ hour.=$\frac{x}{5}$ + $\frac{1}{4}$ hour.

So, $\frac{x}{3}$ – $\frac{3}{4}$ = $\frac{x}{5}$ + $\frac{1}{4}$2x = 15x = 7.5

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