Tanim bought some oranges. He gave $\frac{1}{2}$ of them to his sister, $\frac{1}{4}$ of the remainder to his neighbour, $\frac{3}{5}$ of those \left to his children and had 6 \left in the end. How many oranges did Tanim buy?

Ashifur August 8, 2023 - 16:58

Problem: Tanim bought some oranges. He gave $\frac{1}{2}$ of them to his sister, $\frac{1}{4}$ of the remainder to his neighbour, $\frac{3}{5}$ of those \left to his children and had 6 \left in the end. How many oranges did Tanim buy?

View all: BANGLADESH BANK | ASSISTANT DIRECTOR | WRITTEN QUESTION SOLVE(MATH) | 2010

Correct Answer: 40

Explanation:

Given Fractions =$\frac{1}{2}$,$\frac{1}{4}$,$\frac{3}{5}$

Let, Total number of oranges = 40x

Given sister = 40x x $\frac{1}{2}$= 20x

Rest = 40x — 20x = 20x

Given Neighbor = 20x x $\frac{1}{4}$= 5x

Rest = 20x — 5x =15x

Gave Children = 15x x $\frac{3}{5}$= 9x

Rest = 15x —9x = 6x

According to the question:

6x = 6

x = 1

Total Number of oranges = 40x = 40 x 1 = 40

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