Problem: The length of a rectangle is twice its width. If the length is increased by 4 inches and the width is decreased by 3 inches, a new rectangle is formed whose perimeter is 62 inches. What is the length of the original rectangle?

View all: BANGLADESH BANK (BB) | ASSISTANT DIRECTOR (AD) | WRITTEN QUESTION SOLVE(MATH) | 2011

Correct Answer: 20 inches

Explanation:

Suppose, width = w inch

Length = 2w inch

Area = 2w² sqr inch

Again, the new length = (2w + 4) inch and the new width = (w — 3) inch

According to question;2(2W+4+W—3)=62

(3W + 1) = 31

W = 10

Length of the original rectangle is 2W = 2 x 10= 20 inches

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