Problem: The length of a rectangle is twice its width. If the length is increased by 4 inches and the width is decreased by 3 inches, a new rectangle is formed whose perimeter is 62 inches. What is the length of the original rectangle?
View all: BANGLADESH BANK (BB) | ASSISTANT DIRECTOR (AD) | WRITTEN QUESTION SOLVE(MATH) | 2011
Correct Answer: 20 inches
Explanation:
Suppose, width = w inch
Length = 2w inch
Area = 2w² sqr inch
Again, the new length = (2w + 4) inch and the new width = (w — 3) inch
According to question;2(2W+4+W—3)=62
(3W + 1) = 31
W = 10
Length of the original rectangle is 2W = 2 x 10= 20 inches