ans. $\frac{5}{2}$
x$^{2}$+y$^{2}$
=$(\frac{\sqrt{3+1}}{\sqrt{3-1}})^{2}$+$(\frac{\sqrt{3-1}}{\sqrt{3+1}})^{2}$
= $\frac{5}{2}$
ans: 54 years.
Given years ago Samad was = 12
Now Samad = (12 +$\frac{x}{2}$) year.
Again, afier $\frac{1}{2}$ years Samad will be =12+$\frac{x}{2}$+$\frac{x}{2}$=12+x
According to the question,
12+x=2x
=> x=12
Samad’s present age =12+$\frac{x}{2}$=12+$\frac{12}{2}$=18 years
After 3x years Samad will be = 18 + 3x
=18 + (3 x 12) = 54 years.
ans: 153600 sq.m.
Given that, length : breadth = 3 : 2
Let, the length of the rectangle be 3x and the breadth of the rectangle be 2x
The Area = 3x X 2x = 6x$^{2}$ and the perimeter = 2(3x + 2x) = 10x.
Now,
In 60 minutes the man covers 12km = 12000 meters.
In 1 minutes the man covers 12km = $\frac{1200\times 8}{60}$ =1600 meters.
Now, we get, 10x = 1600
=> x= $\frac{1600}{10}$ =160
Area of the rectangle = 6$^{2}$
= (6 x 160 x 160) sq.m = 153600 sq.m.
ans . $\frac{5N}{2}$
According to the questions, Sedan = $\frac{1}{3}$
Others =(1-$\frac{1}{3}$)= $\frac{2}{3}$
Station wagons =($\frac{1}{5}$of$\frac{2}{3}$)= $\frac{2}{15}$
From the questions,‘ $\frac{2}{15}$ = N
1= $\frac{15N}{2}$
$\frac{1}{3}$= $\frac{15N}{2}$X$\frac{1}{3}$= $\frac{5N}{2}$
