1.08
Total runs from singles, two & threes = 21 + 9 x 2 + 7 x 3 = 60
Total scored ball (six & four) = (120 —68 —21—9— 7) = 15
Let, Fours from 2x balls
Sixes from x balls = 2x + x = 15
x = 5
Sixes from 5 balls = 5 x 6 = 30 runs
Fours from 10 balls = 10 x 4 = 40 runs
Total runs = (30 + 40 + 60) = 130
$\frac{\text{Run}}{\text{Per Ball}}=\frac{130}{120}=1.08$
1:2
Assume , 120 units = 1 unit
A manufactures in 1 hour = $\frac{1}{12}$ portion
Similarly A+B+C manufacture in 1 hour = $\frac{1}{12}$ + $\frac{1}{20}$ + $\frac{1}{30}$ = $\frac{1}{6}$ Portion
A : (A+B+C) = $\frac{1}{12}$ : $\frac{1}{6}$ = 1 : 2
180000
$\frac{1}{3}$ th was invested in stocks. Rest was (1 -$\frac{1}{3}$) =$\frac{2}{3}$ of the fund
in bonds = $\frac{2}{3}$ x 25%=$\frac{1}{6}$ th & in mutual fund = $\frac{1}{6}$ th ofthe fund.
Residual .part = (I -$\frac{1}{3}$-$\frac{1}{6}$-$\frac{1}{6}$) =$\frac{1}{3}$
$\frac{1}{3}$rd of the endowment = 60,000
Total size = 60,000 x 3 = 1,80,000
50 liters
Let, Capacity = x liter.
$\frac{2x}{5}+25=\frac{90}{100}x$
=> 2x + 125 = $\frac{9}{2}$x
=> 4x + 250 = 9x
=> x = 50
Capacity of the fuel tank is 50 liters.
$\frac{K(100+r)}{100-t}$
Profit buying price = $K+\frac{r}{100}xK = K(1+\frac{r}{100})=K\frac{100+r}{100}$
At t% of gross sales value is deducted, then after deduction of t% price must be equal to $K\frac{100+r}{100}$
(100-t)% = $K\frac{100+r}{100}$
=> 1 % = $\frac{K(100+r)}{100(100-t)}x100$
Gross sales price = $\frac{K(100+r)}{100-t}$
