15 workers
Total workers = 160
Time to complete the task = 120 days
Remaining task =$1-\frac{1}{8}=\frac{7}{8}$
So, we get, by 120 days 1 task can be completed by = 160 Workers
By 1 day 1 task can be completed by = 160 x 120 workers.
By 96 days 1 task can be completed by = $\frac{160 x 120}{96}$ workers.
By 1 day $\frac{7}{8}$ task can be completed by =$\frac{160 x 120×7}{96×8}$ workers. = 175 workers.
Addition worker needed = 175 — 160 = 15 workers.
43
Let, the unit digit = x and
The tenth digit = y
The number is 10y + x
According to the first condition of the question
(x + y) + 5 = 3y
x = 3y — y — 5
x = 2y — 5 ———— (i)
Again, after the digit is interchanged then, Unit digit will be y and tenth digit will be x and the interchanged number 10x + y.
According to the Second condition of the question
(10y+x) – (10x +y) = 9
9y-9x= 9
=> 9(y-x) =9 x1
=> y—x = 1 [Divide both side by 9]
=> y—(2y— 5) =1 [From 1]
=> y—2y+5=l
=> y-2y=1—5
=> y=4
Putting the value of y in (i) we have,
x=2x(4)—5= 8—5=3
Thenumber=10y+x=(10x 4)+3 =43.
