The ratio of milk and water in the resultant mixture is 9 : 1.
Sum ofthe ratio = 3 +2 = 5
Amount of milk in the mixture = 20 $\times \frac{3}{5}$ = 12 litre
Amount of water in the mixture = 20$\times \frac{2}{5}$ = 8 litre
After removal of 10 litre mixture, the amount of milk will be = 10$\times \frac{3}{5}$= 6 litres
& After removal of 10 litre mixture, the amount of water will be = 10$\times \frac{2}{5}$ = 4 litres
After pouring 10 litre pure milk, the amount of milk in the new mixture will be = 10 +6 = 16 litres
& the amount of water will remain unchanged, that is 4 litres.
Now the ratio of milk & water in the new mixture will be = 16 : 4 = 4 : 1
After removal of 10 litre mixture, the amount of milk in that mixture will be = 10$\times \frac{4}{5}$= 8 litres
And the amount of water will be = 10$\times \frac{1}{5}$= 2 litres
Now, After addition of 10 litre pure milk in the mixture, the new amount of milk and water will
be (8 + 10) = 18 litres and 2 litres respectively.
The ratio of milk and water in the resultant mixture = 18 : 2 = 9 : 1.
Balam’s speed is 12 meter/secound.
In the first heat, Distance of Balam from Abul is 432m
Now, if Abul takes I minutes, then Balam takes (t +$\frac{1}{10}$) minutes
In the second heat, Distance of Balam from Abul is 336m
So, if Abul takes I minutes, then Balam takes = (t-$\frac{1}{30}$) minutes
Therefore, to run (432 – 336) = 96m, Balam took time ($\frac{1}{30}$+$\frac{1}{10}$) second
As velocrty = $\frac{Distance}{Time}$
So, Speed of Balam = $(\frac{96}{\frac{1}{30}+\frac{1}{10}})$
Speed of Balam = $\frac{96}{\frac{1+3}{30}}$
= $\frac{96}{\frac{4}{30}}$
= 720 meter/minute
= $\frac{720}{60}$meter/secound
= 12 meter/secound