ans: Rimi got 1,875 Tk, Shahnaz got 3,750 Tk and Lipi got 2,250 Tk.
Let, Rimi got Tk. x;
Shahnaz got = 2x Tk. and Lipi got =($\frac{3}{5}$of2x)= $\frac{6x}{5}$ TK
So, we get x + 2x +$\frac{6x}{5}$ =7875
=> $\frac{5x+10x+6x}{5}$ =7875
=> x=1875
2x=1875×2=3750
and $\frac{6x}{5}$ =1875 x $\frac{6}{5}$ =2250 TK
ans: 15 workers.
Total workers = 160
Time to complete the task = 120 days
Remaining task = (1-$\frac{1}{8}$) = $\frac{7}{8}$
So, we get, by 120 days 1 task can be completed by = 160 Workers
By 1 day 1 task can be completed by = 160 x 120 workers.
By 96 days 1 task can be completed by = $\frac{160\times 120}{96}$ workers.
By 1 day $\frac{7}{8}$ task can be completed by = $\frac{160\times 120\times7}{96\times8}$ = 175 workers.
Addition worker needed = 175-160 = 15 workers.
