12.5 days.
(2 men + 3 boys)’s 10 days work = (3 men + 2 boys)’s 8 days works.
=> (20 men + 30 boys)’s 1 day work = (24 men + 16 boys)’s 1 day work.
=> 4 men = 14 boys
=> 1 men = $\frac{14}{4}$ boys
=> 2 men = $\frac{14}{4}$ X 2 boys = 7 boys.
2 men + 3 boys = 7 boys + 3 boys = 10 boys
and 2 men +1 boy= 7 boys + 1 boy = 8 boys
10 boys can do the work in = 10 days
8 boys can do the work in = $\frac{10\times 10}{8} = 2\frac{1}{2}$ Or, 12.5 days.
Original and reduced price 81 Tk and 7.5 Tk respectively.
At $6\frac{1}{4}$% reduction, price of sugar = (100-$\frac{25}{4}$) = ($\frac{400-25}{4}$)tk = $\frac{375}{4}$ TK
If original pnce IS 100 TK then reduced price = $\frac{375}{4}$ TK
If original price is 120 Tk, then reduced price = $\frac{375\times 120}{4\times 100}$ = 12.5 TK
The reduced price of sugar = (120 – 112.5) = 7.5 TK
Now, If reduced price Is $\frac{375}{4}$ tk, then original price = 100 1k
If reduced price is 7.5 tk, then original price = $\frac{100×7.5×4}{375}$= 8 Tk.
Tk. 650 & Tk. 900
Let, x tk is lent out at 8% interest
(1550 -x) tk is lent out at 6% interest
According to question
X $\times$ 8% x 1 +(1550 – x) $\times$ 6% x 1=106
=> $\frac{8X}{100}$ + $\frac{(1550-x)x6}{100}$=106
=> 8x + 9300 – 6x =10600
=> 2x = 10600 – 9300
=> 2x= 1300 ‘
x = 650.
650 tk is lent out at 8% interest and (1550 — 650) = 900Tk lent out at
