Problem: A father divides his property between his two sons A and B. A invests the amount at compound profit of 8% p.a. B invests the amount at 10% p.a. simple profit. At the end of 2 years, the profit received by B is TR. 1336 more than the profit received by A. Find the share of A in the father’s property of Tk. 25,000.

Correct Answer: ans. A পায়  10000 টাকা

Explanation:

Let, A gets Tk. x

B gets Tk. (25000 – x)

At the end of two years, the interest A gets Tk. = x $(1+\frac{8}{100})^{2}$- x

= x $(\frac{27}{25})^{2}$ -x

= $\frac{729x}{625}-x$

= $\frac{729x-625x}{625}$

= $\frac{104x}{625}$

And, at the end of two years, the interest B gets = Tk. $\frac{(25000-x)\times 10\times 2}{100}$= TK $\frac{(25000-X)}{5}$

According to question,

$\frac{(25000-X)}{5}$- $\frac{104x}{625}$ = 1336

=> $\frac{3125000-125x-104x}{625}$

=> 3125000 – 229x = 835000

=> 3125000 – 835000 = 229x

=> 229000 = 229x

x = 10000