Problem: A person invested $\frac{2}{3}$ rd of his capital at th at 3%,$\frac{1}{6}$ th at 6% and the remainder at 12%. Find out the amount of capital if his annual income is Tk. 25.
View all: RAJSHAHI KRISHI UNNAYAN BANK (SO)| 1$^{st}$ CLASS WRITTEN QUESTION (MATH) SOLVE | 2015
Correct Answer: ans: 500 Tk.
Explanation:
Let, the capital be x Tk.
$\frac{2}{3}$ rd of his capital be $\frac{2x}{3}$ TK
$\frac{1}{6}$ th of his capital be $\frac{x}{6}$
Rest of the capital be = $(x-\frac{2x}{3}-\frac{x}{6})$
= $\frac{6x-4x-x}{6}$ = $\frac{x}{6}$
According to the question.
$(\frac{2x}{3}\times \frac{3}{100}\times 1)$ + $(\frac{x}{6}\times \frac{6}{100}\times 1)$ = 25
=> $\frac{x}{50}+\frac{x}{50}+\frac{x}{50}$ = 25
=> $\frac{2x+x+2x}{100}$ = 25
=> 5x =100×25
=> $\frac{25\times 100}{5}$
x = 500 TK