Problem: A place of stone fell from a balloon when it was flying in the upward direction with a velocity 20 m/scc. What will be the height of the balloon when the stone hit the ground in 10 seconds?
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Correct Answer:
Explanation:
h =ut+$\frac{1}{2}gt^{2}$
= (20×20)+$\frac{1}{2}$x9.8×10$^{2}$
= 200+490
= 690 m
বেলুনর ক্ষেত্রে,
h = ut+$\frac{1}{2}gt^{2}$
= (20×20)+$\frac{1}{2}$x9.8×10$^{2}$
=200-490
=-290m
= 290m
u=20ms$^{-1}$;g=9.8ms$^{-2}$; t=10 second
so, The total higth of ballon is =(690+290)m = 980m