Problem: A place of stone fell from a balloon when it was flying in  the upward direction with a velocity 20 m/scc. What will be the height of the balloon when the stone hit the ground in 10 seconds?

View all: BANGLADESH BANK LTD (OFFICER) WRITTEN QUESTION (MATH) SOLVE | 2018

Correct Answer:

Explanation:

h =ut+$\frac{1}{2}gt^{2}$

= (20×20)+$\frac{1}{2}$x9.8×10$^{2}$

= 200+490

= 690 m

বেলুনর ক্ষেত্রে,

h = ut+$\frac{1}{2}gt^{2}$

= (20×20)+$\frac{1}{2}$x9.8×10$^{2}$

=200-490

=-290m

= 290m

u=20ms$^{-1}$;g=9.8ms$^{-2}$; t=10 second

so, The total higth of ballon is =(690+290)m = 980m

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