Problem: In a cricket game a batsman played 120 balls. His hits of four were twice the number of hits of sixes. He hit 21 singles, 9 twos and 7 threes. If he failed to score of 68 deliveries. What was his average score per ball?

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Correct Answer: 1.08

Explanation:

Total runs from singles, two & threes = 21 + 9 x 2 + 7 x 3 = 60

Total scored ball (six & four) = (120 —68 —21—9— 7) = 15

Let, Fours from 2x balls

Sixes from x balls = 2x + x = 15

x = 5

Sixes from 5 balls = 5 x 6 = 30 runs

Fours from 10 balls = 10 x 4 = 40 runs

Total runs = (30 + 40 + 60) = 130

$\frac{\text{Run}}{\text{Per Ball}}=\frac{130}{120}=1.08$

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