Problem: A can do a piece of work in 10 days, while B alone can do it in 15 days. They work together for 5 days and the rest of the work is done by C in 2 days. If they get Tk. 4500 for the whole work, how should they divide the money?

View all: BASIC BANK OFFICER (AO) | WRITTEN QUESTION (MATH) SOLVE | 2014

Correct Answer: ans: A gcts Tk 2250; B \gets  TK. 1500 & C \gets Tk TK. 750.

Explanation:

In 10 days A does 1 work

In 1 day A does $\frac{1}{10}$ the work

In 5 days A does $\frac{5}{10}$ = $\frac{1}{2}$ of work

Again, In 15 days B does 1 work

In 1 day B does $\frac{1}{15}$ of the work

In 5 days B does $\frac{3}{15}$ = $\frac{1}{3}$ of the work

In 5 day \both A & B together do = ( $\frac{1}{2}$+ $\frac{1}{3}$) = $\frac{5}{6}$ Work

Rest =(1- $\frac{5}{6}$) = $\frac{1}{6}$ work

In 2 day C docs $\frac{1}{6}$ of work

A:B:C:= $\frac{1}{2}$: $\frac{1}{3}$: $\frac{1}{6}$ =3:2:1

A \gets Tk = $\frac{3}{6}$x 4500 = TK. 2250

B \gets Tk = $\frac{2}{6}$x 4500 = TK. 1500

C \gets TK = $\frac{1}{6}$x 4500 = TK. 750

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