A female worker of a factory serves on the basis of monthly salary. At the end of every year she gets a fixed increment. Her monthly salary becomes TR. 4500 after 4 years of service and TR. 5000 after 8 years of service. Find the salary at the beginning of her service and the amount of annual increment of salary.

Ashifur August 8, 2023 - 13:21

Problem: A female worker of a factory serves on the basis of monthly salary. At the end of every year she \gets a fixed increment. Her monthly salary becomes TR. 4500 after 4 years of service and TR. 5000 after 8 years of service. Find the salary at the beginning of her service and the amount of annual increment of salary.

View all: UNION BANK (SO) | WRITTEN QUESTION (MATH) SOLVE | 2014

Correct Answer: ans: Increment is 125 tk. salary at beginning is 4000 TK

Explanation:

After 8 years salary is 5000 tk.

After 4 years salary is 4500 tk.

4 years salary difference = 500 tk.

1 years salary difference = $\frac{500}{4}$ = 125 tk.

At beginning, salary was [4500 = (125 x 4)] = 4000 tk.

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