Abul and Balam ran, at their respective constant rates, a race of 480m. In the first heat, Abul gives Balam a head start of 48m and beats him by$\frac{1}{10}$ th of a minute. In the second heat, Abul gives Balam a head start of 144m and is beaten by $\frac{1}{30}$th of a minute. What is Balam’s speed in m/s?

Ashifur August 8, 2023 - 19:06

Problem: Abul and Balam ran, at their respective constant rates, a race of 480m. In the first heat, Abul gives Balam a head start of 48m and beats him by$\frac{1}{10}$ th of a minute. In the second heat, Abul gives Balam a head start of 144m and is beaten by $\frac{1}{30}$th of a minute. What is Balam’s speed in m/s?

View all: DUTCH BANGLA BANK (PO) WRITTEN QUESTION (MATH) SOLVE | 2016

Correct Answer: Balam’s speed is 12 meter/secound.

Explanation:

In the first heat, Distance of Balam from Abul is 432m

Now, if Abul takes I minutes, then Balam takes (t +$\frac{1}{10}$) minutes

In the second heat, Distance of Balam from Abul is 336m

So, if Abul takes I minutes, then Balam takes = (t-$\frac{1}{30}$) minutes

Therefore, to run (432 – 336) = 96m, Balam took time ($\frac{1}{30}$+$\frac{1}{10}$) second

As velocrty = $\frac{Distance}{Time}$

So, Speed of Balam = $(\frac{96}{\frac{1}{30}+\frac{1}{10}})$

Speed of Balam = $\frac{96}{\frac{1+3}{30}}$

= $\frac{96}{\frac{4}{30}}$

= 720 meter/minute

= $\frac{720}{60}$meter/secound

= 12 meter/secound

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