Ashifur August 8, 2023 - 19:52
Problem: If 7 percent of the sale price of a product is equal to 8 percent of its cost price and 9 , percent of the sale price exceeds 10 percent of the cost price by Tk. I, find the amount of profit and the cost price of the product. 

View all: SOUTHEAST BANK OFFICER (TO) | WRITTEN QUESTION (MATH) SOLVE | 2016

Correct Answer: Profit 50 Tk. & Cost price 350 Tk.

Explanation:

Let, the sale price of the product is Tk. x

& the cost price of the product is Tk. y

7% of sale price is Tk. 7% of x = $\frac{7x}{100}$

8% of cost price is Tk. 8% of y = $\frac{8y}{100}$

According to the question, $\frac{7x}{100}$ = $\frac{8y}{100}$

According to the question, $\frac{7x}{100}$ = $\frac{8y}{100}$

=> 7x = 8y 

=> x = $\frac{8y}{7}$……….(i)

Again, 9% of sale price is Tk. 9% of x = $\frac{9x}{100}$

10% of cost pr1ce is Tk. 10% of y = $\frac{10y}{100}$

Aecordin to the qestion , $\frac{9x}{100}= \frac{10y}{100}$+1

=> $\frac{9x}{100}$ = $\frac{10y+100}{100}$

=> 9x = 10y+100

=> 2y = 700

y = 350

Now putting the value of y in equation (i), we get

x = $\frac{8\times 350}{7}$

=> x = 400

Cost price of the product is Tk. 350 & the sale price of the products is Tk. 400

Profit = 400 -350 = 50 Tk.

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