Problem: If S is added to the sum of the digits of a number consisting of two digits, the sum will be three times of the digit of the tens place. Moreover, if the places of the digits are interchanged, the number thus found will be 9 less than the original number. Find the number.
View all: DHAKA BANK | WRITTEN QUESTION (MATH) SOLVE | 2016
Correct Answer: 43
Explanation:
Let, the unit digit = x and
The tenth digit = y
The number is 10y + x
According to the first condition of the question
(x + y) + 5 = 3y
x = 3y — y — 5
x = 2y — 5 ———— (i)
Again, after the digit is interchanged then, Unit digit will be y and tenth digit will be x and the interchanged number 10x + y.
According to the Second condition of the question(10y+x) – (10x +y) = 9
9y-9x= 9
=> 9(y-x) =9 x1
=> y—x = 1 [Divide both side by 9]
=> y—(2y— 5) =1 [From 1]
=> y—2y+5=l
=> y-2y=1—5
=> y=4
Putting the value of y in (i) we have,
x=2x(4)—5= 8—5=3
The number=10y+x=(10x 4)+3 =43.