Problem: If $\sqrt[3]{x^{2}\sqrt{x}\sqrt{\frac{1}{4}}}$ = $\frac{1}{\frac{1}{\frac{1}{\frac{1}{x}}}}$ what is the valu of x ?

View all: SOCIAL ISLAMI BANK (PO) | WRITTEN QUESTION (MATH) SOLVE | 2014

Correct Answer: ans .0, 1

Explanation:

R.H.S = $\frac{1}{\frac{1}{\frac{1}{\frac{1}{x}}}}$

= $\frac{1}{\frac{1}{X}}$ [ $\frac{1}{\frac{1}{X}}$= x]

= X

L.H.T = $\sqrt[3]{x^{2}\sqrt{x}\sqrt{\frac{1}{4}}}$

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