Problem: A cistern can be filld in 10 hours but it takes 12 hours due to a leak in its \bottom. If ‘the cistern is full, then how much time the leak will take to empty the cistern?

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Correct Answer: ans: 60 hours time is needed for the leak to empty the cistern.

Explanation:

As the cistern can be filld in 10 hours but it takes 12 hours due to a leak in its \bottom

Work done by the cistern in 1 hour = ($\frac{1}{10} -\frac{1}{12}$)

= $\frac{6-5}{60}$

= $\frac{1}{60}$

$\frac{1}{60}$ Part of the cistern is emptied in 1 hour

1 or Full part of the cisterm is emptied in =$\frac{1×60}{1}$ = 60 hours

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