Problem: A person sells two articles. Each for the same price Tk. 1,040. He incurs 20% loss on the first and 10% loss on the second. Find his overall percentage of loss.

View all: BANGLADESH BANK OFFICER | WRITTEN QUESTION (MATH) SOLVE | 2015

Correct Answer: ans: His overall 15.294% of loss.

Explanation:

At 20% loss, if cost price is Tk. 100, then selling price = Tk. (100 – 20) = Tk. 80

Now, while selling price is Tk. 80, then cost price = Tk. 100

While selling price is Tk. 1, then cost price = $\frac{100}{80}$ Tk.

While selling price is Tk. 1,040, then cost price = $\frac{100×1040}{80}$ = Tk. 1,300

Again, at 10% less, if cost price is Tk. 100, then selling price = Tk. (100 – 10) = Tk. 90While selling price is Tk. 90, then cost price = Tk. 100

While selling price is Tk. 1, then cost price = Tk. $\frac{100}{90}$

While selling price is Tk. 1040, then cost price = TK. $\frac{100×1040}{90}$ =TK. $\frac{10400}{9}$

Total selling price of two articles = 2 x 1,040 = Tk. 2,080

And Total cost price of two artIcles = Tk. (1300 +$\frac{10400}{9}$)= Tk. ($\frac{11700+10400}{9}$) = TK. $\frac{22100}{9}$

Overall loss percentage = $\frac{(\frac{22100}{9}-2080)}{\frac{22100}{9}}$ x 100%

= $\frac{\frac{22100-18720}{9}}{\frac{22100}{9}}\times 100$%

= ($\frac{3380}{9}$x$\frac{9}{22100}$)x100%

=15.294%

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