Correct Answer: 1%

Explanation:

Let, cost price of frist shirt = x Tk.

cost price of second shirt = y TK

According to the question

x+x$\times$10%= y-y$\times$10%

=> x+$\frac{10x}{100}$ = y- $\frac{10y}{100}$

=> $\frac{10x+x}{10}$ = $\frac{10y+y}{10}$

=> 11x = 9y

=> $\frac{x}{y} = \frac{9}{11}$

That means cost price of first shirt 9 Tk. & second shirt 11 Tk.

Total cost = 9 + 11 = 20 Tk.

Now at 10% profit on first shirt the selling price will be = 9 + 9 X 10% = 9.9Tk.

At 10% loss on second shirt the selling price will be = 11 – 11 x 10% = 9.9Tk.

Total selling price will be = 9.9 + 9.9 = 19.8 Tk.

Loss amount = 20 – 19.8 = 0.2 Tk.

Percentage of loss = $\frac{0.2}{20}$ x 100 = 1%

Loss 1% (ans)