Problem: Each edge of the cube shown in the figure has length L. What is the perimeter of ABDE?

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Correct Answer: 3$L\sqrt{2}$

Explanation:

CE=BC=CD=L

BD = Diagonal of ABCD

AB² + AD² = BD²

L² + L² = BD²

BD = $L\sqrt{2}$

Thus, BE = DB = BD = $L\sqrt{2}$

Perimeter = $L\sqrt{2}$ + $L\sqrt{2}$ + $L\sqrt{2}$= 3$L\sqrt{2}$

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