Problem: Each edge of the cube shown in the figure has length L. What is the perimeter of ABDE?
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Correct Answer: 3$L\sqrt{2}$
Explanation:
CE=BC=CD=L
BD = Diagonal of ABCD
AB² + AD² = BD²
L² + L² = BD²
BD = $L\sqrt{2}$
Thus, BE = DB = BD = $L\sqrt{2}$
Perimeter = $L\sqrt{2}$ + $L\sqrt{2}$ + $L\sqrt{2}$= 3$L\sqrt{2}$