Problem: If $\frac{x+2y}{a+3b}=\frac{y+3x}{a+4b}$ ,then prove that the $\frac{x}{x}=\frac{a+5b}{2a+5b}$
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Correct Answer: See explanation
Explanation:
$\frac{x+2y}{a+3b}=\frac{y+3x}{a+4b}$
=>(x+2y) (a+4b)=(y+3x) (a+3b)
=>ax+4bx+20y+8by=ay+3by+3ax+9bx
=>2ax+5bx=ay+5by
=>x(20+ 5b) =y(a+ 5b)
$\frac{x}{x}=\frac{a+5b}{2a+5b}$