Problem: Mr. X sold 2 properties, P1. and P2 for Tk. 1,00,000 each. He sold property P1 for 20% less than what he paid for it. What is the percentage of profit of property P2 so that he is not in gain or loss, on the sale of the two properties?
View all: ONE BANK LTD | PROBETIONARY OFFICER | WRITTEN QUESTION SOLVE(MATH) | 2008
Correct Answer: $31\frac{1}{3}$ %
Explanation:
As property P.1 is 20% less than purchase price,
Purchase of P1= 100000 x $31\frac{100\%}{80\%}$= Tk. 125000
Loss = Tk. 25000
Mr X made profit from P2 = Tk. 25000
The purchase price of P2 was = Tk. 100000 — Tk. 25000= T k. 75000
Profit in P2 was =$31\frac{25000}{75000}x100$ = $31\frac{1}{3}$ %
