Problem: The perimeter of a square field is equal to the perimeter of a rectangular field. Length of the rectangular is 3 times of its width and the area is 768 square meter. How many square sized tiles of 80 centimeter width will be required to cover the square field?
View all: MODHUMOTI BANK LTD (PO) WRITTEN QUESTION (MATH) SOLVE | 2018
Correct Answer: 1,600
Explanation:
Let the width of the rectangular field be x meter
Length of the rectangular field is 3x meter
According to the question, 3x$\times$x= 768
=> 3x$^{2}$ = 768
=> x$^{2}$ = $\frac{768}{3}$
=> x$^{2}$ = 256
so, x=16
so, length= 3 X 16 = 48 meter and width = 16 meter
so, Perimeter = 2(48 + 16) = 128 meter
Perimeter of square = Perimeter of rectangular field
so, Perimeter of square = 128 meter
so, Side of square = $\frac{128}{4}$ = 32 meter = 32 X 100 = 3200cm
so, Area of square field = (3200 x 3200) sq.cm.
Area of tiles = (80 X 80) sq.cm.
so, Number of Required tiles = $\frac{3200×3200}{80×80}$ =1,600