Problem: A and B can complet a work in 15 days 10 days respectively. They started doing the work together but after 2 days B had to leave and A alone completed the remaining work. How many days did it took to complete the whole work?

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Correct Answer: Time taken to complete the work = 10+2 = 12 days

Explanation:

(A+B)” s 1 days,s work = $(\frac{1}{15}+\frac{1}{10})$ = $\frac{1}{6}$ part

so, (A+B), 2 days,s work = $\frac{2}{6}$ = $\frac{1}{3}$ part

Remaining work =$(1- \frac{1}{3})$ part

Now, $\frac{1}{15})$ part of work is done by A in 1 day

so, $\frac{2}{3})$ part of work is done by A in = $\frac{15×2}{3×1})$ = 10 day

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