Problem: If x+$\frac{1}{x}$ = 2,What is the value of $\frac{x}{x^{2}+x-1}$?
View all: SHAJALAL ISLAMI BANK(TO CACH) | WRITTEN QUESTION (MATH) SOLVE | 2016
Correct Answer: The value is 1.
Explanation:
x+$\frac{1}{x}$ = 2
=> $\frac{x^{2}+1}{x}$ = 2
=> $x^{2}$+1=2x
=> $x^{2}$-2x+1=0
=> $x^{2}$-2x$\times 1+1^{2}$ = 0
=> (x-1)$^{2}$ = 0
=> x-1=0
x=1
$\frac{x}{x^{2}+1-1}$
= $\frac{1}{1^{2}+1-1} $
= $\frac{1}{1}$
= 1
