Correct Answer: $622.37cm^{3}$

Explanation:

Radius of semi Circular sheet. r = $\frac{28}{2}$= 14 cm

so, Circumference of the sheet = $pi$r= ( $\frac{22}{7}$x 14) = 44cm Here. circumference of semi circle will be equal to the circumference of the base of cone.

Now. let the radius of the base of cone = R

According to question = 2$pi$R = 44

=> R = $\frac{44}{2pi}=\frac{44}{\frac{22\times }{7}}=44\times \frac{7}{22\times 2}$ = 7cm

Here. radius of semi circle equals to the height of cone.that mean’s I = r = 14cm

Now. we know I$^{2}$ = h$^{2}$+R$^{2}$= h$^{2}$ = I$^{2}$ – R$^{2}$

=> h$^{2}$=(14)$^{2}$-(7)$^{2}$=196-49 = 147

=> h = $\sqrt{49\times 3}=\sqrt{7^{2}\times 3}= 7\sqrt{3}$

so, h = $7\sqrt{3}$

So. the depth is $7\sqrt{3}$ cm and

The capacity will be = $(\frac{1}{3}pi^{2h})=(\frac{1}{3}\times\frac{22}{7}\times 7^{2}\times 7\sqrt{3})=622.37cm^{3}$