Problem: If 2x= 4y = 8z and $\frac{1}{2x} + \frac{1}{4y} + \frac{1}{4z} = 4$, then find the value of x.
View all: UCBL BANK | OFFICER | WRITTEN MATH QUESTION SOLVE | 2010
Correct Answer: $\frac{1}{2}$
Explanation:
Given, 2x= 4y = 8z or x= 2y = 4z
$\frac{1}{2x} + \frac{1}{4y} + \frac{1}{4z} = 4$,
=> $\frac{1}{2x} + \frac{1}{2x} + \frac{1}{x} = 4$
=> $\frac{1}{2x} (\frac{1}{2} + \frac{1}{2} + 1)= 4$
=> x = $\frac{1}{2}$
