Correct Answer:  220 ways. 

Explanation:

Here, 3 members is to be included in

Available men = 7 & Available women = 5

so, the combination can be

(i) $^{7}C_{3}x ^{5}C_{0} = \frac{7!}{3!x4!} x \frac{5!}{5!x0!}$ = 35

(ii) $^{7}C_{2}x ^{5}C_{1} = \frac{7!}{2!x5!} x \frac{5!}{1!x4!}$ = 105

(iii) $^{7}C_{1}x ^{5}C_{2} = \frac{7!}{1!x6!} x \frac{5!}{2!x3!}$ = 70

(iv) $^{7}C_{0}x ^{5}C_{3} = \frac{7!}{7!x0!} x \frac{5!}{3!x2!}$ = 10

so, total combination = 35 + 105 + 70 + 10 = 220 ways.