Problem: A tank can be filled up by tap X in 20 minutes and by tap Y in 60 minutes. Both the tap are kept open for 10 minutes and then tap X is closed. What is the total time required to fill up the tank?

View all: BASIC BANK | ASSISTANT OFFICER | WRITTEN QUESTION SOLVE (MATH) | 2009

Correct Answer: 30 minutes

Explanation:

Tap X in 20 minutes can fill 1 portion

Tap X in 10 minutes can fill =$\frac{10}{20}$=$\frac{1}{3}$ portion

Tap Y in 60 minutes can till 1 portion

Tap X in 10 minutes can fill$\frac{10}{60}$
=$\frac{1}{6}$portion

In 10 minutes tank filled =$\frac{1}{3}$ +$\frac{1}{6}$  portion=$\frac{2}{3}$

Remainmg = 1 –$\frac{2}{3}$=$\frac{1}{3}$portion

Tap Y can fill 1 portion in 60 minutes

Tap Y can $\frac{1}{3}$ portion in 60 x$\frac{1}{3}$= 20 minutes

Total time required = (10 + 20) = 30 minutes

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