Ashifur September 9, 2023 - 17:37
Problem: Resolve into factors: a$^{2}$+$\frac{1}{a^{2}}$+2-2a-$\frac{2}{a^{a}}$

View all: BANGLADESH KRISHI BANK LTD (OFFICER-CASH) WRITTEN QUESTION (MATH) SOLVE | 2018

Correct Answer: $(a+\frac{1}{a})(a+\frac{1}{a}-2)$

Explanation:

Given , a$^{2}$+$\frac{1}{a^{2}}$+2-2a-$\frac{2}{a^{a}}$

= a$^{2}$+$(\frac{1}{a})^{2}+2-2a\frac{2}{a}$

= $= (a+\frac{1}{a})^{2}-2\times a\times \frac{1}{a}+2-2a-\frac{2}{a}$

= $(a+\frac{1}{a})^{2}$-2+2-2a-$\frac{2}{a}$

= $(a+\frac{1}{a})^{2}$-2a-$\frac{2}{a}$

= $(a+\frac{1}{a})$($(a+\frac{1}{a})$-($(a+\frac{1}{a})$

= $(a+\frac{1}{a})(a+\frac{1}{a}-2)$

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