ans: Per unit labour cost Tk. 12 per unit capital cost TR. 25
Correct Answer: ans: Per unit labour cost Tk. 12 per unit capital cost TR. 25
Explanation:
By using 5 units labour + 3 units capital total cost comes Tk. 135…….(I)
By using 4 units labour + 2 units capital total cost comes Tk. 98…….(II)
By deducting, 1 unit labour + 1 unit capital = TK. 37…….(iii)
Multiply equations (iii) by 5
5 units labour + 5 units capital =185 ……..(iv)
5 units labour +3 units capital =135……….(v)
By deducting,
2 unit capital = Tk. 25
Putting value of equation (iv),
we have, 5 units labour + (5 x 12.2) = 185
=>5 Units labour= 185-61
=> 5 Units labour =124
=>1 Units labour = Tk. 24.8
ans: 3.5% Increase.
Suppose, the cost of the product per unit Tk. 100
100 unit cost Tk. (100 x 100) = Tk. 10000
Selling price decreases by 10% per unit cost =(100-10) -=TR. 90
But, sale (in unit) increase 15% 100 unit grow in (100 + 15) = Tk. 115
So, 115 unit’s costTk. =(115 x 90) = Tk. 10350
Total change cost Tk. =(10350 – 10000) = Tk. 350
In percentage = $\frac{350\times 100}{10000}$=3.5%
ans. 14
Suppose, in the box
K pencils are x in numbers
L pencils are 2x in numbers
j pencils are (32 – 3x) in numbers
According to the question.
(32 -3x) x 0.05 + 2x 0.10+x$\times$0.25 = 3.40
=>$\frac{(32-3x)\times 5}{100}$+$\frac{2x}{10}+\frac{25x}{100}$=$\frac{34}{10}$
x=6
The number of J pencil in the box are =32-3x
= 32-3 x 6 = 14
ans: Tk. 655.0625
As Mr. Karim took loan for 5% interest
So, after 3 years Mr. Karim has to paid along with interest=tk.$\frac{115\times 10000}{100}$=11500 tk
But Mr. Rahim compounded the loan account quarterly.
Then Rahim has to calculated = 10000 ($1+\frac{5}{100}^{4}$)=TK.12155.0625
Mr. Karim needs to pay extra money = Tk. (12155.0625-115800)=TK. 655.0625
Question 5:
ans: 10 month.
Total amount Tk. 2500
Monthly instalments Tk. 250
Requtred time that entire amount Will be paid=$\frac{2500}{250}$=10 month.
