ans: 2,250 Tk.
Let, Kalam’s meal cost be x Tk.
Bashar’s meal cost = x + (50% of x) = $\frac{3x}{2}$ Tk.
Abul s meal cost = $\frac{3x}{2}$x $\frac{5}{6}$ = $\frac{15}{12}$ = $\frac{5x}{4}$
According to question, Kalam’s meal cost x = 1,000 Tk.
Abul’s meal cost = $\frac{5x}{4}$ = $\frac{5\times 1000}{4}$ = 1,250 Tk.
Total meal cost of Kalam & Abul = 1,000 + 1,250 = 2,250 Tk.
ans. 400 TK
1n 6 days Abdul can finish the whole = 1 work
In 1 day Abdul can finish the whole = $\frac{1}{6}$ part of the work
Again,
In 8 days Bokul can finish the whole = 1 work
In 1 day Bokul can finish the whole =$\frac{1}{8}$ part of the work
So, In 1 both Abdul & Bokul together can finish = ($\frac{1}{6}$+ $\frac{1}{8}$) = $\frac{7}{24}$ part of the work
Again in 3 days, Abdul, Bokul & Chinu can finish the whole = 1 work
In 1 day, Abdul, Bokul & Chinu can finish the whole =$\frac{1}{3}$part of the work
In 1 day only Chinu can finish = $\frac{1}{3}-\frac{7}{24}= \frac{1}{24}$ part of the work
So, the ratio of 1 day’s work done by Abdul, Bokul & Chinu respectively = $\frac{1}{6} : \frac{1}{8} : \frac{1}{24}$ = 4:3:1
Chinu is to be paid = (3200 x $\frac{1}{4+3+1}$) = 400 Tk.
