Answer:
So, 60 liters water needs to be added.
Explanation:
Sum of the given ratio = 2 + 1 = 3
Quantity of milk = (60 of $\frac{2}{3}$) = 40 liters
Hence, quantity of water will be = 60 – 40 = 20 liters
Assume. x liters water needs to be added.
According to question, $\frac{40}{x+20}=\frac{1}{2}$
=> x + 20 = 80
=> x = 80 – 20 = 60
x = 60
So, 60 liters water needs to be added.
Answer:
$\sqrt{x-\frac{1}{\sqrt{x}}}=\frac{24}{5}$
Explanation:
Given x=3+22
=> x=25
=> 5$^{2}$=x
=> 5=$\sqrt{x}$
so, $\sqrt{x}$=5
Now, $\sqrt{x}$-$\frac{1}{\sqrt{x}}=5-\frac{1}{5}$
=$\frac{25-1}{5}=\frac{24}{5}$
=>$\sqrt{x-\frac{1}{\sqrt{x}}}=\frac{24}{5}$