The amount deposited at 7% is Tk 1,000.
Let, at 6% rate, Mr. Rahim deposited = x Tk.
at 7% rate,.he deposited = 4,000 – x Tk.
at 6% rate, total interest = $\frac{6\times x\times 1}{100}$
at 7% rate, total Interest = $\frac{7\times (4000-x)\times 1}{100}$
According to question, $\frac{6\times x\times 1}{100}$+$\frac{7\times (4000-x)\times 1}{100}$ = 250TK
=> $\frac{6X}{100}+\frac{28000-7x}{100}$ = 250 TK
=> 6x + 28,000 – 7x = 25,000 Tk.
=> x = 25,000-28,000 Tk.
=> x = 3,000 Tk.
At 7% interest rate, he deposited = 4,000 – 3,000 = 1,000 Tk.a
His asking price was 81.25 Tk.
Let, total income of the salesman = 100 Tk.
He earns from commission = 1,000 – 250 = 750 Tk.
If 15 Tk. is commission then total sales = 100 Tk.
If 1 Tk. is commission then total sales = $\frac{100}{15}$ Tk.
lf 750 Tk. is commission then total sales = $\frac{100\times750}{15}$= 5,000 Tk.
The area of the field 8,800 Sq. feet.
Let, the width = x feet
the length = x + 30 feet
We know, perimeter = 2(Length + breadth)
Perimeter = 2(x + 30 + x)
According to the question
2(x + 30 +x) = 380
=> 4x + 60 = 380
=> 4x = 380 – 60
x = 80 feet.
The length is = 80 + 30 = 110 feet
Area =110 x 80 Sq. feet
= 8,800 Sq. feet
60 minute
1$^{st}$ tap takes 30 minutes to till 1 part of the tank
1$^{st}$ tap takes 1 minute to fill $\frac{1}{30}$ pan of the tank
Again, 2$^{nd}$ tap takes 40 minutes to drain 1 part of the tank
2$^{nd}$ tap takes 1 minute to drain $\frac{1}{40}$ part of the tank
in 1 minute,
Two taps fill ($\frac{1}{30}$-$\frac{1}{40}$ ) part of the tank
= $\frac{1}{120}$ part of the tank
Now, $\frac{1}{120}$ part of the tank is filled in = 1 minute
$\frac{1}{2}$ part of the tank is filled in =$\frac{120}{2}$ = 60 minute
