ans: 12%.
Let, the trader bought x dozens of mangoes & x dozens of apples.
1 dozen mango costs = 150 Tk.
x dozen mango costs = 150x TK.
1 dozen apple costs = 100 Tk.
x dozen apple costs = 100x Tk.
(x + x) = 2x dozens fruits cost (150x + 100x) = 250x Tk.
Again, Selling price 1 dozen of fruits = 140 Tk.
Selling price 2x dozen of fruits = 2x $\times$140 = 280x Tk.
Profit percentage =$\frac{30x}{250x}$ $\times$100 = 12%.
ans: 56%.
A : B = 70 : 30
=> B =$\frac{3A}{7}$
Now, 20% share in the business = 10,00000 Tk.
100% share in the business =$\frac{ 10,00000\times 100}{20}$= 50,00000 Tk.
Therefore, A + B + C = 50,00000
=> A +$\frac{3A}{7}$+10,00000 = 50,00000
=>$\frac{3A+7A}{7}$ = 40,00000
=> A = 28,00000.
Amount of A share is 28,00000 Tk.
Percentage of share =$\frac{50,00000}{28,00000}$ x 100 = 56%.
$16\frac{2}{3}$%.
At 25% profit
If cost price is Tk 100, then selling price would be 125 Tk.
If selling price is 125 tk. then cost price would be = 100 Tk.
[f selling price is 4000 tk. then cost price would be = $\frac{100×4000}{125}$
= 3,200 Tk.
Total cost price of two commodities = 4,000 + 4,000 = 8,000 Tk.
Then the cost price of another commodity = 8,000 — 3,200 = 4,800 Tk.
But the sold another commodity at 4,000 Tk.
So he loses = 4,800 — 4,000 = 800 Tk.
Loss%=$\frac{800}{4800}$x 100 =$16\frac{2}{3}$%.
1
ans: 25
Here, area of PQRS = 48 and
Breadth, PQ = 6
Length, PS =$\frac{48}{6}$= 8.
Diagnal of the rectangular is = $\sqrt{6^{2}+8^{2}}$ = $\sqrt{100}$ = 10.
Radius =$\frac{10}{2}$=5
& the area of the circle = 5$^{2}$ x π = 25π
ans: 2,000.
Let, the principle be Tk. x
We know in the case of compound interest c = p$(1+\frac{r}{100})^{n}$
=> x + 420 = x $(1+\frac{10}{100})^{2}$
=> x + 420 =x $(1+\frac{1}{10})^{2}$
=> x+ 420 = x $\times$ $(\frac{11}{10})^{2}$
=> x+ 420 = $\frac{121x}{100}$
=> 100x + 42,000 =121x
=> 21x=42,000
=> x = $\frac{42,000}{21}$
x=2,000.
